$begingroup$ Sorry, I'm really slow at getting these things to click for me. So let me see if I can break it down for myself and maybe you can see where I'm going wrong. So basically the $T(E)$ equation is derived in the book and it represents the period of a nonlinear pendulum. The question is asking us to show that the period of a nonlinear is greater than the period of a linear. So to do that we set the inequality. I guess what I'm not getting is why the RHS represents the period of a linear pendulum.
An output square wave whose amplitude is proportional to acceleration. Phase sensitive demodulation techniques are then used to rectify the signal and determine the direction of the acceleration.” The accelerometer outputs a voltage that is proportional to the force acting on the sensing element. Techniques for the Oscillated Pendulum and the Mathieu Equation Joe Mitchell Abstract. Square wave approximations (the flrst turning the nonlinear equation into the so called. Nonlinear ODEs, because within a certain neighborhood of an equilibrium point, a nonlinear equation usually acts like a linear equation. (This linear equation is.
Like I said, I know how you got it, by setting $E=0$, but what does it represent exactly? $endgroup$–Feb 9 '14 at 16:50.